P=2x^2+16x+340

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Solution for P=2x^2+16x+340 equation: 



=2P^2+16P+340

We move all terms to the left:

-(2P^2+16P+340)=0

We get rid of parentheses

-2P^2-16P-340=0

a = -2; b = -16; c = -340;
Δ = b2-4ac
Δ = -162-4·(-2)·(-340)
Δ = -2464
Delta is less than zero, so there is no solution for the equation

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